60x^2+64x-256=0

Solution for 60x^2+64x-256=0 equation:

60x^2+64x-256=0

a = 60; b = 64; c = -256;
Δ = b2-4ac
Δ = 642-4·60·(-256)
Δ = 65536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65536}=256$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-256}{2*60}=\frac{-320}{120}
=-2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+256}{2*60}=\frac{192}{120}
=1+3/5
$